Quotient-9 shadow rigidity

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Status: proved theorem inside the Type A/B minimal-depth/shadow program

Date: 2026-08-15

Project: Free Computation Foundation / CENTL

Claim boundary: this does not prove universal Direct-Shadow Completeness, López Type A/B coverage, or the Erdős-Straus conjecture. It completely classifies unrestricted full direct shadows along the ancestry quotient q=9.

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1. Quotient-9 ancestry

Fix a source depth j>=1, put

m=4j-1,

and define its quotient-9 ancestry child

\boxed{K=9j-2.}

Then

4K-1=9(4j-1)=9m.

Thus this is exactly the odd-square lift with square multiplier

9=3^2.

Also

\boxed{K\equiv j\pmod m}

and

\boxed{4K\equiv1\pmod m.}

2. Normalized trap sets

It is convenient to negate the trap sets. Define

S_n=-T_n = \{e,4e\pmod{4n-1}:e\mid n\}.

The set S_n is inverse-closed. Indeed, if e|n and f=n/e, then

(4e)f=4n\equiv1\pmod{4n-1},

so

(4e)^{-1}\equiv f,

and conversely.

For the ancestry pair (j,K), if e f=K, then modulo m

(4e)f=4K\equiv1.

Therefore, once every divisor residue e mod m belongs to S_j, all companion residues 4e mod m belong as well by inverse closure.

Hence:

Lemma

For K=9j-2,

\boxed{ T_K\bmod m\subseteq T_j \iff e\bmod m\in S_j\quad\text{for every divisor }e\mid K. }

This reduces quotient-9 full shadowing to the image of the target divisor lattice.

3. Classification theorem

Theorem

Let

K=9j-2.

Then the complete unrestricted target layer is shadowed by j if and only if exactly one of the following occurs:

  1. K is prime;
  2. K=2p with p prime;
  3. (j,K)=(2,16).

Equivalently,

\boxed{ T_{9j-2}\bmod(4j-1)\subseteq T_j \iff \begin{cases} 9j-2\text{ is prime},\quad\text{or}\\ (9j-2)/2\text{ is prime},\quad\text{or}\\ j=2. \end{cases} }

In the second alternative j is automatically even because 9j-2 is even.

4. Prime child direction

If K is prime, the general prime-child ancestry theorem applies immediately:

\boxed{T_K\bmod m\subseteq T_j.}

5. Twice-prime child direction

Suppose

K=2p

with p prime.

Then K is even, so j is even. Put

d=j/2.

Since

K=9j-2,

we have

p=\frac K2=\frac{9j-2}{2}.

Subtract d=j/2:

p-d = \frac{8j-2}{2} =4j-1 =m.

Therefore

\boxed{p\equiv d=j/2\pmod m.}

The divisors of K=2p are

1,2,p,K.

Modulo m these become

1,\quad2,\quad j/2,\quad j,

and every one is a divisor of j.

Thus every target divisor residue lies in S_j, so by the normalized-divisor lemma

\boxed{T_K\bmod m\subseteq T_j.}

6. Exceptional child K = 16

For

j=2,

we get

K=16, \qquad m=7.

The normalized base trap set is

S_2=\{1,2,4\}\pmod7.

Every divisor of 16 is a power of two, and its residue modulo 7 lies in

\{1,2,4\}.

Therefore

\boxed{T_{16}\bmod7\subseteq T_2.}

This is the unique composite child in the quotient-9 classification that is neither prime nor twice a prime.

7. Converse when j is odd

Assume j is odd. Then K=9j-2 is odd.

Suppose K is composite. Let ell be its smallest prime factor. Then

\ell\le\sqrt K.

For every composite odd child beyond the tiny initial range,

\sqrt K<4j-1=m,

and the few initial values are checked directly. In fact the inequality already holds for every relevant odd j>=1 with composite K.

Also

\gcd(j,K) = \gcd(j,9j-2) = \gcd(j,2) =1,

so

\ell\nmid j.

Because ell is an odd integer with

1<\ell<m,

it cannot be a member of the normalized base set S_j:

  • it is not a divisor of j;
  • every unwrapped value 4d with d<j is divisible by 4, hence cannot equal odd ell;
  • the only wrapped endpoint 4j reduces to 1.

Thus

\ell\notin S_j.

But ell|K, so the normalized-divisor lemma says full shadowing fails.

Therefore, when j is odd,

\boxed{ T_K\bmod m\subseteq T_j \iff K\text{ is prime}. }

8. Converse when j is even

Now let

j=2d.

Then

K=18d-2 =2N,

where

\boxed{N=9d-1.}

Also

N-m = (9d-1)-(8d-1) =d,

because

m=4j-1=8d-1.

Hence

\boxed{N\equiv d=j/2\pmod m.}

Suppose N has an odd prime factor ell.

Choose the smallest such factor. Since ell|N and

\gcd(N,d)=\gcd(9d-1,d)=1,

we have

\ell\nmid j.

Also ell<m except for the prime case N=ell itself. If N is composite with an odd prime factor, choosing a proper prime factor gives ell<=sqrt N<m.

As above, an odd ell with 1<ell<m and ell not|j cannot lie in S_j.

Therefore full shadowing forces either:

  1. N is prime, giving the twice-prime family K=2N; or
  2. N has no odd prime factor, so
N=2^r.

We must classify the second possibility.

9. The power-of-two residual is unique

Suppose

N=9d-1=2^r.

Then

2^r\equiv-1\pmod9.

The powers of 2 mod 9 have period 6, and -1 mod 9 occurs exactly when

\boxed{r\equiv3\pmod6.}

For r=3,

N=8, \qquad d=1, \qquad\j=2, \qquad K=16,

which is the exceptional shadow already found.

Now suppose r>=9. Then d=(2^r+1)/9 is odd, so

j=2d

has exact 2-adic valuation 1.

The target depth is

K=2N=2^{r+1},

so 16|K and therefore 16 is a target divisor.

For r>=9,

16<m=8d-1.

But 16 cannot lie in S_j:

  • 16 is not a divisor of j, because v_2(j)=1;
  • if 16=4e in the unwrapped second family, then e=4, but 4 not|j;
  • the wrapped endpoint is only 1.

Hence the target divisor 16 escapes the base normalized trap set.

Therefore no r>=9 works.

So the unique power-of-two residual is

\boxed{j=2,\ K=16.}

Combining all cases proves the classification theorem. QED.

10. Structural interpretation

The quotient-5 theorem said:

\boxed{q=5:\quad\text{full unrestricted shadow}\iff\text{child prime}.}

The new quotient-9 theorem says:

\boxed{ q=9:\quad \text{full unrestricted shadow} \iff \text{child has divisor lattice of prime / twice-prime type, plus }16. }

This is the first exact evidence that composite-child shadowing is controlled by the factorization shape of the child depth itself.

The square multiplier 9=3^2 permits one extra divisor coordinate, but only in an extremely rigid way.

11. Infinite shadow subfamilies

The theorem gives several infinite families.

Prime children

Prime children satisfy

K\equiv-2\equiv7\pmod9.

Dirichlet gives infinitely many primes in this class, hence infinitely many quotient-9 prime-child shadows.

Twice-prime children

Write

K=2p=9j-2.

Then

p\equiv-1\equiv8\pmod9.

Every prime

p\equiv8\pmod9

gives

j=\frac{2p+2}{9} =\frac{2(p+1)}9

and hence a quotient-9 full shadow.

Dirichlet gives infinitely many such primes.

Therefore the quotient-9 graph has at least two infinite arithmetic components:

\boxed{ K\text{ prime},\ K\equiv7\pmod9, }

and

\boxed{ K=2p,\quad p\text{ prime},\ p\equiv8\pmod9. }

12. Counting

For child depths K<=X, the prime component has asymptotic count

\pi(X;9,7) \sim \frac{1}{6}\frac{X}{\log X}.

The twice-prime component corresponds to primes

p\le X/2, \qquad p\equiv8\pmod9,

and therefore has asymptotic count

\pi(X/2;9,8) \sim \frac{1}{12}\frac{X}{\log X}.

Ignoring their disjoint tiny exception, quotient 9 therefore contributes

\boxed{ \left(\frac14+o(1)\right) \frac{X}{\log X} }

unrestricted full-shadow child depths up to X.

13. Next theorem target

The next ancestry quotient is

\[ q=13, \qquad K=13j-3.</div>

Unlike 9, the quotient is prime rather than a square. The prime-child family is automatic, but composite children may obey a different rigidity law.

The broader target is now clear:

For each fixed ancestry quotient q=4s+1, classify the factorization types of the child depth K=qj-s for which every target divisor residue is absorbed by the base divisor/inverse set.

Quotients 5 and 9 are now completely solved in the unrestricted system.

14. Novelty boundary

Divisor arguments, Dirichlet's theorem, and elementary congruences are classical. López Type A/B congruences are prior art.

The candidate contribution is the exact quotient-9 ancestry shadow classification in the C_AB minimal-depth/shadow framework, extending the prime-child theorem into a genuinely composite-child rigidity theorem.

Publication priority remains subject to external review and broader prior-art search.