Odd-prime-shift ancestry rigidity above the small-ancestor window

Ancestry · hosted from the CENTL repository

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Ancestry

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Status: proved universal theorem

Date: 2026-08-15

Project: Free Computation Foundation / CENTL

Claim boundary: unrestricted Type A/B trap-set shadowing only. The theorem applies for j>=s+1. Small j can contain additional full-shadow children and is a separate exception problem. This does not prove Direct-Shadow Completeness, López Type A/B coverage, or the Erdős-Straus conjecture.

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1. Setup

Let r>=3 be an odd prime and put

Q=4r+1, \qquad K=Qj-r, \qquad m=4j-1.

No primality assumption on Q is required.

Assume

\boxed{j\ge r+1.}

2. The theorem

Theorem

For every odd prime r and every j>=r+1,

\boxed{ T_K\bmod m\subseteq T_j \iff \left( K\text{ is prime} \quad\text{or}\quad K=r p\text{ with }p\text{ prime} \right). }

In the second alternative necessarily

r\mid j.

Thus above the explicit small-ancestor window, the entire unrestricted full-shadow structure of an odd-prime shift is exactly the divisor-child family.

3. Direct implication

The divisor-child theorem applies with shift s=r.

Since r is prime, the only divisors of r are

a=1,r.
  • a=1 gives prime children;
  • a=r gives K=rp when r|j.

Hence both stated shapes are fully shadowed.

4. Converse from the asymptotic skeleton

Because r is odd and j>=r+1, the odd-shift asymptotic skeleton applies.

Therefore a fully shadowed child satisfies exactly one of:

  1. K is r-smooth;
  2. K=a p with
a\mid\gcd(j,r),

and p prime.

Since r is prime, the second case is already

K=p\quad\text{or}\quad K=rp.

It remains only to eliminate the smooth branch.

5. Elimination of smooth children

If K is r-smooth, then

K=r^u

for some integer u>=1.

The ancestry equation gives

r^u=(4r+1)j-r,

hence

\boxed{ j=\frac{r^u+r}{4r+1}.}

u = 1

Then

j=\frac{2r}{4r+1}<1,

impossible.

u = 2

Integrality would require

4r+1\mid r+1,

because gcd(r,4r+1)=1.

But

0<r+1<4r+1,

impossible.

u = 3

Integrality requires

4r+1\mid r^2+1.

Use the exact identity

16(r^2+1)-(4r+1)(4r-1)=17.

Therefore

4r+1\mid17.

For odd prime r>=3,

4r+1\ge13.

The only positive divisors of 17 at least 13 are 17 itself, which would give

r=4,

not an odd prime.

Thus u=3 is impossible.

u >= 4

The child modulus relation gives

m=\frac{4r^u-1}{4r+1}.

For every r>=3 and u>=4,

\boxed{m>r^2.}

Indeed it is enough to check u=4:

4r^4-1>r^2(4r+1),

which is equivalent to

4r^4-4r^3-r^2-1>0,

true for r>=3.

But r^2 is a divisor of K=r^u and satisfies

1<r^2<m.

Also

\gcd(j,K)=\gcd(j,r),

so

r^2\nmid j.

Because r^2 is odd, it cannot be of the form 4e for a divisor e|j. Hence

r^2\notin S_j.

This contradicts full shadowing.

Therefore no r-smooth full-shadow child exists.

The converse is complete. QED.

6. Why Q need not be prime

The proof uses only

Q=4r+1\equiv1\pmod4

for modulus ancestry and the arithmetic identity defining K.

It does not require Q itself to be prime.

Thus the theorem simultaneously contains:

  • r=3, Q=13;
  • r=5, Q=21;
  • r=7, Q=29;
  • r=11, Q=45;
  • and every later odd-prime shift.

For the first few shifts, existing exact quotient-specific theorems additionally handle the finite small range j<=r.

7. Small-j exceptions really exist

The threshold j>=r+1 cannot simply be deleted.

For example,

r=17, \qquad j=2, \qquad K=121, \qquad m=7.

Then

S_2=\{1,2,4\}\pmod7

and the divisors 1,11,121 reduce to 1,4,2, so full shadowing holds even though K is neither prime nor 17p.

Other small-window examples include:

r=19, j=4:  K=289=17^2
r=53, j=4:  K=799=17*47
r=71, j=8:  K=2209=47^2
r=83, j=2:  K=583=11*53

These are governed by the exact multiplicative structure of the small ancestor S_j, not by the large-j factor-size mechanism.

8. Structural interpretation

The theorem separates odd-prime-shift ancestry into two regimes:

\boxed{ \begin{array}{c} 1\le j\le r\\ \text{small-ancestor multiplicative exceptions possible} \end{array} }

versus

\boxed{ \begin{array}{c} j\ge r+1\\ \text{full shadow}\iff\text{prime or }rp \end{array} }

So the apparent infinite quotient-by-quotient complexity is actually concentrated into a finite-width diagonal strip j<=r.

Outside that strip, every odd-prime shift has exactly the same rigidity law.

9. Next target

Classify the small-ancestor exception strip

\boxed{1\le j\le r}

as r varies over odd primes.

For fixed j, the normalized ancestor trap set S_j is fixed, while

K=r(4j-1)+j

varies linearly with r.

Thus the exception problem becomes:

classify prime parameters r for which every divisor of r(4j-1)+j lies inside the fixed finite residue set S_j modulo 4j-1.

At dyadic ancestors j=2^a, the earlier Mersenne theorem gives

S_j=\langle2\rangle,

turning the condition into a concrete multiplicative-subgroup factorization problem.

That is the correct next layer of the ancestry diamond.