Multiplicative Type A/B trap coset

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Status: proved structural theorem and active proof direction

Date: 2026-08-14

Project: Free Computation Foundation / CENTL

Claim boundary: this note does not prove universal Direct-Shadow Completeness, López Type A/B coverage, or the Erdős-Straus conjecture. López 2024 already records the Type B Jacobi-nonresidue fact and explicitly notes the mutual-inverse relationship between the Type A and Type B divisor residues. The subgroup/coset packaging below is being treated as a novelty candidate pending broader literature review.

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1. Setup

For k>=1, put

m_k=4k-1

and

T_k=\{-e,-4e\pmod{m_k}:e\mid k\}.

Let

G_k=(\mathbb Z/m_k\mathbb Z)^\times.

Define the divisor-generated subgroup

\boxed{ H_k=\langle \ell\bmod m_k:\ell\text{ prime and }\ell\mid k\rangle \le G_k. }

Equivalently, H_k is generated by the residue classes of the prime divisors of k.

2. Trap-coset theorem

Theorem

For every k>=1,

\boxed{T_k\subseteq -H_k.}

Moreover,

\boxed{-1\notin H_k,}

so H_k and -H_k are distinct disjoint cosets.

Proof

Every divisor e|k is a product of prime divisors of k, hence

e\in H_k.

Also k itself lies in H_k. Since

4k\equiv1\pmod{4k-1},

we have

4\equiv k^{-1}\pmod{m_k},

and therefore

4\in H_k.

Thus, for every e|k, both e and 4e belong to H_k, so

-e,-4e\in-H_k.

Hence

T_k\subseteq-H_k.

To prove that the two cosets are distinct, use the Jacobi character

\chi_k(a)=\left(\frac{a}{m_k}\right).

For every prime divisor ell|k, the divisor-Jacobi calculation already recorded in QUADRATIC-TRAP-SIGNATURE.md gives

\chi_k(\ell)=+1.

Therefore chi_k is identically +1 on the subgroup generated by those primes:

\chi_k(h)=+1\qquad(h\in H_k).

But m_k=3 mod 4, so

\chi_k(-1)=-1.

Thus -1 cannot lie in H_k. Consequently H_k and -H_k are distinct cosets. QED.

3. The quadratic theorem is only a projection

The previous quadratic theorem says

T_k\subseteq\ker(\chi_k-(-1)),

or more simply that every trap has Jacobi sign -1.

The trap-coset theorem is strictly more informative:

\boxed{ T_k\subseteq-H_k \subseteq \{u\in G_k:\chi_k(u)=-1\}. }

The Jacobi character is therefore one quotient character of the larger finite quotient

\boxed{G_k/H_k.}

The quadratic signature remembers only one bit of this quotient geometry.

4. Trap-coset index

Define

\boxed{ \iota(k)=[G_k:H_k] =\frac{\varphi(m_k)}{|H_k|}. }

Because -1 notin H_k but the Jacobi character is trivial on H_k, iota(k) is always even and

\boxed{\iota(k)\ge2.}

Since every Type A/B trap lies in one coset of H_k, at least

\boxed{1-\frac1{\iota(k)}}

of the unit residue classes modulo m_k are automatically Type-A/B-safe before the exact divisor subset inside -H_k is examined.

When iota(k)>2, this is strictly stronger than the quadratic +1 shield, which certifies only one half of the unit group.

This does not say that every element of -H_k is a trap. Usually T_k is far smaller than the complete coset. The coset is a structured outer envelope.

5. Full quotient-character formulation

Let

\widehat{G_k/H_k}

be the character group of the quotient. Every character in this group may be viewed as a multiplicative character on G_k that is trivial on H_k.

The coset -H_k is characterized by

\boxed{ x\in-H_k \iff \psi(x)=\psi(-1) \text{ for every }\psi\in\widehat{G_k/H_k}. }

Therefore a single quotient character satisfying

\boxed{ \psi(x)\ne\psi(-1) }

certifies that x cannot be a Type A/B trap at depth k.

The Jacobi shield is the special order-two case obtained from the character chi_k.

This suggests a multiplicative coset shield stronger than the quadratic shield: exploit the full quotient G_k/H_k, not merely its Jacobi image.

6. Inversion structure and prior-art boundary

For e|k, write d=k/e. Then

(-e)^{-1}\equiv-4d\pmod{m_k},

and

(-4e)^{-1}\equiv-d\pmod{m_k}.

Thus T_k is closed under inversion. López 2024 already explicitly notes that the Type A and Type B divisor residue sets are mutual inverses, so that fact is not claimed here as new.

The subgroup envelope is compatible with this symmetry because

(-H_k)^{-1}=-H_k.

7. Finite exact signal through k = 1200

An independent exact enumeration through k<=1200 verifies the theorem layer by layer and shows that the quotient can be much richer than one quadratic bit.

Across those 1200 layers:

  • iota(k) is always even;
  • the median index is 2;
  • the mean index is about 7.5183;
  • the largest observed index is
\boxed{\iota(683)=210,}

where

m_{683}=2731, \qquad \varphi(2731)=2730, \qquad

|H_{683}|=13.</div>

Thus the entire Type A/B trap set at that layer lies inside a coset occupying only

\frac1{210}

of the unit group.

Other large observed indices include 176, 162, 160, 144, 128, and 108.

These finite values are diagnostics, not asymptotic claims.

8. Why this matters for Direct-Shadow Completeness

The current proof architecture was

\text{exact traps} \to \text{quadratic character shield} \to \text{fixed-negative character core} \to \text{exact trap avoidance}.

The trap-coset theorem inserts a stronger intermediate layer:

\boxed{ \text{exact traps} \subset \text{one multiplicative coset} \subset \text{Jacobi-negative half}. }

So a candidate that is Jacobi-negative at an earlier layer may nevertheless be immediately safe because it occupies a different coset of H_j.

The next proof problem is therefore not merely quadratic. It is a finite-abelian quotient problem.

9. New theorem targets

  1. compute G_k/H_k canonically from the prime-power decomposition of m_k;
  2. determine how much of the fixed-negative character core is eliminated by higher-order quotient characters;
  3. formulate a simultaneous quotient-character shield across earlier layers;
  4. compare the quotient-character residual core with the fiber shadow kernel;
  5. prove candidate-independent bounds on the quotient complexity needed for exact-depth realization;
  6. determine whether the remaining exact trap core is confined to a finite family of small quotient signatures.

The high-value question is now:

Is the quadratic character core only the first visible shadow of a much stronger multiplicative quotient obstruction theory?

If so, the unexplained overlap in the Type A/B covering system may be encoded by G_k/H_k rather than by raw residue density.