Corridor
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Status: proved universal strengthening of FAB-KNESER-DIVISOR-DEFECT.md
Date: 2026-08-15
Depends on: FAB-KNESER-DIVISOR-DEFECT.md
Claim boundary: compresses every failed fixed-k FAB product box once its full stabilizer is taken. It does not prove that some auxiliary k must always succeed and therefore does not prove Erdős-Straus.
1. Setup
Let
and let
be the fixed-k signed divisor box.
Assume its exact FAB target is missed.
Let
be the full stabilizer, and put
Write
By construction,
For each prime factor define
2. No local factor may fill its projected subgroup
Suppose r_i notin H, so d_i>1.
Its local signed set in the quotient is
If
then the consecutive exponent interval contains representatives of every residue modulo d_i. Therefore
But then
is invariant under multiplication by the nontrivial subgroup
That contradicts the trivial stabilizer of \bar R.
Hence:
Theorem — projected-order gap
For every prime-power factor outside the full stabilizer,
Equivalently,
This conclusion uses the exact stabilizer, not merely the Kneser size inequality.
3. Universal exceptional-valuation bound
FAB-KNESER-DIVISOR-DEFECT.md proves the Kneser budget
For every r_i notin H, the projected-order theorem gives
so its contribution is exactly
For every r_i in H, the contribution is zero.
Therefore the entire Kneser budget collapses to
Hence:
Theorem — full-stabilizer defect mass
Every failed fixed-k FAB signed divisor box satisfies
Thus the total prime-factor valuation visible outside the stabilizer is universally bounded by half the quotient size.
No primality assumption on the quotient index is needed.
4. Interpretation
Write
where C_H contains all prime powers with residue class in H, and C_exc contains the rest.
Then every failed exact placement has two simultaneous properties:
Large hidden background
All prime-power factors of C_H are invisible in the quotient defect.
Tiny visible defect
The total valuation
satisfies
Moreover every exceptional prime has projected order strictly larger than twice its exponent plus one.
So a target miss is possible only when almost all shifted-factor mass collapses into one stabilizer subgroup and the visible quotient is supported by a short list of high-order atoms.
5. Recovery of earlier classifications
Index 3
The mass bound gives
so every factor lies in H.
Index 5
Thus there is at most one simple exceptional factor.
Index 6
The projected-order gap excludes quotient orders 2 and 3 for every exceptional factor. Only order 6 remains. The external-nonresidue parity then reduces the possibilities further to the unique-simple-defect theorem in FAB-KNESER-INDEX6-CLASSIFICATION.md.
Index 10
Every exceptional factor must have quotient order exceeding 2e+1. In the cyclic order-ten quotient this immediately excludes:
- all order-two projections;
- order-five projections of exponent at least two;
- order-ten projections of exponent at least five.
This sharply reduces the next mixed classification before any case analysis begins.
6. Contrapositive expansion criterion
For any candidate subgroup H<=G_k, if the prime factorization of C=(p+k)/4 has too much valuation outside H, namely
then H cannot be the full stabilizer of a failed divisor box.
Likewise, if any factor outside H has
then H cannot be the full defect stabilizer.
Thus a proof can eliminate candidate defect subgroups using only:
- quotient orders of the actual shifted prime factors;
- their valuations.
No exhaustive enumeration of all signed divisors is required.
7. Entropy-or-descent formulation
At an external-nonresidue factor-cycle vertex, the same shifted integer carries both:
- a guaranteed external nonresidue factor for the descent edge;
- a hypothetical Kneser defect subgroup if exact placement fails.
The full-stabilizer theorem says that the failure subgroup must hide almost all factor valuation, leaving only a bounded collection of high-order visible atoms.
Therefore the universal program can be stated more sharply as:
The remaining all-prime task is to prove that such a tiny high-order defect cannot persist around every external-nonresidue cycle.