Theorem
Let p == 1 (mod 4) be prime and let r == 3 (mod 4) be an odd positive integer such that
Status: proved exact reformulation
Date: 2026-08-15
Depends on: BINARY-R-RESCUE.md
Claim boundary: this converts the exact binary rescue condition into a finite multiplicative collision problem. It does not prove that such a collision always occurs.
1. Setup
Let p == 1 (mod 4) be prime and let r == 3 (mod 4) be an odd positive integer such that
Put
Then
By BINARY-R-RESCUE.md, the binary remainder splits if and only if there is a divisor
with
The argument below does not require r prime, only gcd(N,r)=1.
2. Every divisor of N^2 is a signed divisor ratio around N
Write
A divisor
can be written
where x,y|N.
Indeed, for each prime put
The positive z_i exponents form x and the negative exponents form y.
Conversely, for any x,y|N,
is an integer divisor of N^2: primewise its exponent lies between 0 and 2e_i.
Because gcd(N,r)=1, every divisor of N is invertible modulo r.
Therefore
is equivalent to
hence to
3. Divisor-collision theorem
Let
Then the following are equivalent:
- the binary-r remainder
r/Nsplits into two unit fractions; - there is
d|N^2withd == -N (mod r); - there are divisors
x,y|Nwith
- the divisor residue set meets its negative:
-1lies in the ratio set
Thus the fixed-r ES problem is a signed divisor collision, not an arbitrary search through all divisors of N^2.
4. Signed exponent-box formulation
With
the collision exists if and only if there are integers
such that
This is the exact multiplicative analogue of a bounded symmetric exponent box hitting one distinguished group element.
It is structurally close to the two-box and defect-quotient machinery already developed in the Type A/B shadow program, but here the target is the actual Erdős–Straus decomposition rather than exact-depth realizability.
5. Pigeonhole escape
Since negation is a bijection of the unit group modulo r,
Therefore, if
then the two sets must intersect and the binary-r rescue is automatic.
For prime r, this is simply
Failure forces the divisor residues into at most half of the available unit classes.
This gives a clean theorem-mining target: prove divisor-residue expansion past the half-group threshold, or classify every multiplicatively compressed exception.
6. Exact reciprocity bridge for prime r
Now assume r is prime and r == 3 (mod 4).
Let q be any odd prime divisor of
Then
Because p == 1 (mod 4), quadratic reciprocity gives
Since r == 3 (mod 4), reciprocity between r and q gives
Hence
Therefore
So a prime factor of the shifted integer A_r is a quadratic nonresidue modulo r if and only if it is an external quadratic nonresidue modulo the hard prime p.
This is an exact bridge from FAB-HARD-NONRESIDUE-BRIDGE.md into the direct binary-r rescue.
7. Consecutive-translate interpretation
Put
For
we have
Thus the prime-r program probes the divisor geometry of consecutive translates of the original Eisenstein-split neighbor:
for r=3,7,11,19,23,31,....
The finite first-hit histogram in BINARY-R-RESCUE.md is therefore evidence about a sequence of exact multiplicative collision problems on nearby translates, not a collection of unrelated congruence tricks.
8. New all-prime target
A sufficient universal theorem now has the sharply stated form:
For every Mordell-hard prime
p, there exists an oddr == 3 (mod 4)withgcd(r,pA_r)=1such that the signed divisor exponent box of <div class="math" role="math">> N_r=pA_r
></div>
contains
-1modulor.
For prime r, failure means a multiplicatively compressed divisor set of size at most (r-1)/2; every nonresidue prime entering A_r is simultaneously an external nonresidue of p by the reciprocity bridge.
This is the current direct ES proof target.